If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x^2-5+8x=0
a = 4; b = 8; c = -5;
Δ = b2-4ac
Δ = 82-4·4·(-5)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-12}{2*4}=\frac{-20}{8} =-2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+12}{2*4}=\frac{4}{8} =1/2 $
| 4(x•3)=180/3 | | 12x+25-35=14X+22X-2 | | (X+1)÷5=x÷10 | | 25(x+4)÷5=21×8÷7 | | X+5=2-3x+12 | | 12x^2+24x-96=0 | | x/1.5/3=x/12 | | x/9-8=-1 | | 4d*2(4d+7=-106 | | 4d+2(4d+7=106 | | -43=5c+4(2c+7) | | 1100t=16t^2 | | 5^9x=2.6 | | X²+5x-6=0 | | 5/4+1/5=-5/3x+3/4x | | 29/20=-11/12x | | 2x/4+10=20 | | d=3*7 | | -11=5y+4-y-4 | | 9/10=-29/12u | | 103=2u+3-3u+5 | | 7(t+2)=4(t-4) | | -5s+3(5s+2)=-126 | | 3f+3(-3f+5)=81 | | 25+2k=21 | | 2/5+1/2=-5/3u-3/4u | | 2/5x+15÷5=19 | | 25-2k=21 | | (2/5x+15)÷5=19 | | x-9=-15=7x | | 2x-2=82x=10x=5 | | -8+4u=-36 |